I always knew integrating in a common way:
$\int_{n}^{z}{x^y} \ dx=[\frac{z^{y+1}}{y+1}] - [\frac{n^{y+1}}{y+1}]$
All we do is integrate $x^y$ and then replace the $x$ with $z$ first, then subtract it with itself but instead of replacing $z$, we replace $n$. But then I have seen that:
$e^z = \int_{-\infty}^{z}{e^x} \ dx ≠ [e^z] - [e^{-\infty}]$
Because $e^{-\infty}$ is undefined.
Question is, do we use limits for the second term? Unless, then how do we calculate such an integral?
Thanks for the answers.
An integral $$ \int_{-\infty}^b f(x)dx $$ is understood as $$ \lim_{a\to-\infty}\int_{a}^b f(x)dx, $$ if such limit exists.