I have a maybe obvious question is this true?
$$ r = \int_0^{2\pi} \mathrm{d}\theta f(\theta) e^{i\theta} \implies \frac{\mathrm{d}}{\mathrm{d} \theta}(r) = 0 $$
Or should I differentiate first, and then do the definit integral?
I have a maybe obvious question is this true?
$$ r = \int_0^{2\pi} \mathrm{d}\theta f(\theta) e^{i\theta} \implies \frac{\mathrm{d}}{\mathrm{d} \theta}(r) = 0 $$
Or should I differentiate first, and then do the definit integral?
The definite integral $r = \int_0^{2\pi}\mathrm{d}\theta f(\theta) e^{i\theta}$ is a number provided that it's defined.
$\dfrac{d}{d\theta} r = 0$ because you are differentiating a number $r$ that doesn't change with $\theta$ with respect to a variable $\theta$.