In Rotman's An Introduction to Algebraic Topology, he defines the exterior power as:
If $M$ is an $A$-module and $p\ge0$, then the $p$th exterior power of $M$, denoted by $\bigwedge^pM$, is the abelian group with the following presentation:
Generators: $A\times M\times\dots\times M$ ($p$ factors $M$).
Relations: Some list of relations (I can type them up/screenshot them if needed)
He goes on to say:
If $F$ is the free abelian group with basis $A\times M\times\dots\times M$ and if $S$ is the subgroup of $F$ generated by the relations, then the coset $(a,m_1,\dots,m_p)+S$ is denoted by $am_1\wedge\dots\wedge m_p$. Thus every element of $\bigwedge^pM$ has an expression (not necessarily unique) of the form $\sum_ja_jm_1^j\wedge\dots\wedge m_p^j$ where $a_j\in A$ and $m_i^j\in M$.
I'm a bit confused by how $S$ is different from $\bigwedge^pM$. They seem to be defined the same way. In particular, $F$ seems to just be $\bigwedge^pM$ without the relations, so by adding in the relations (which gives us the exterior power), we should also get $S$. Obviously, this is wrong, but if someone could explain why, that'd be great.
Thanks!
$S$ is the submodule (of $F$) generated by the relations while $\bigwedge^p M$ is the quotient module $F/S$.