By the definition of Riemann integrals I have to show that: $\int_{-a}^{a} f(x^2) dx=2\int_{0}^{a} f(x^2) dx$ (given that both integrals exist)
I thought to approach it as: $\int_{-a}^{a} f(x^2) dx=\int_{-a}^{0} f(x^2) dx+\int_{0}^{a} f(x^2) dx$. And somehow to show that integrals are equal to each other on the right side, but I am not sure how to approach the problem.
Note that $f(x^2)$ is even since $f((-x)^2)=f(x^2)$. So$$\begin{align}\int_{-a}^af(x^2)\text{d}x&=\int_{-a}^0f(x^2)\text{d}x+\int_0^af(x^2)\text{d}x\\&=\int_0^af(x^2)\text{d}x+\int_0^af(x^2)\text{d}x\\&=2\int_0^af(x^2)\text{d}x.\end{align}$$