Deformations using the Bayes' theorem

Question

I couldn't do the following deformations using the Bayes' theorem:
$$p(\phi|x,\eta) = \frac{p(\phi,x|\eta)}{p(x|\eta)} = \frac{p(x|\phi)p(\phi|\eta)}{p(x|\eta)}$$ I can understand that the first deformation can be done by $p(\phi| x, \eta) \cdot p(x|\eta) = p(\phi, x | \eta)$, but I couldn't figure out how to bring the third from the second.