Degree of the continuous map $S^1 \times S^1 \rightarrow S^2$.

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In my course “Introduction to the algebraic topology” I’ve got the following exam problem:

Construct continuous map $S^1 \times S^1 \rightarrow S^2$, which degree is non-zero. Calculate the degree of this map.

I believe that my problem is understanding the concept of the degree. $S^1 \times S^1$ and $S^2$ are obviously orientable manifolds, so there top homology groups are isomorphaic to $\mathbb Z$. Any continuous map $f$ induces homomorphism of this groups $f_*$. By definition, degree of $f$ is just an image of $[1]$ (generator) under $f_*$.

So I need some hints how degree can be calculated in practice, i.e. some examples.

Thanks!

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Look at the quotient map $S^1 \times S^1$ to $S^2$ by collapsing the subspace $S^1 \vee S^1$ to a point( basically taking smash product of circle with circle). This quotient map induces isomorphism on top homology groups hence degree is non zero.