How can I find a genereal solution of this equation:
$(\frac{d \tau}{d t})^2=(\frac{d \theta}{d t})^2+a^2$
Is this the genereal solution ?
$\frac{d \tau}{d t}=\omega$
$\frac{d \theta}{d t}=\sqrt{\omega^2-a^2}$
resulting in:
$(\frac{\tau-\tau_0}{t-t_0 })^2=(\frac{\theta-\theta_0}{t-t_0 })^2+a^2$