Derivative of divided differences

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Let's define function:

$$g:\mathbb C \ni x \rightarrow f[a_1, a_2,...,a_n, x] \in \mathbb C$$

for $f \in C^{n + 1}$

I want to check the differentiability of function $g$ depending on $a_1, a_2,...,a_n$.

My work so far

If we consider point $x_0 \in \mathbb C$, our function will be differentiable when exists limit $\lim_{x \rightarrow x_0}\frac{g(x) - g(x_0)}{x - x_0}$.

Let's rewrite this formula:

$$\lim_{x \rightarrow x_0} \frac{g(x) - g(x_0)}{x - x_0} = \lim_{x \rightarrow x_0}\frac{f[a_1, a_2,...,a_n, x] - f[a_1, a_2, ..., a_n, x_0]}{x - x_0}$$

Now, I can permutate expressions within divided difference:

$$f[a_1, a_2,...,a_n, x, x_0] = f[x_0, a_1,...,a_n, x]$$

to obtain:

$$f[a_1, a_2,..., a_n, x, x_0] = f[x_0, a_1,...,a_n, x] = \frac{f[a_1,...,a_n, x] - f[x_0,x_1,...,a_n]}{x - x_0}= $$

$$=\frac{f[a_1,a_2,...,a_n, x] - f[a_1,a_2,...,a_n,x_0]}{x - x_0}$$

So:

$$\lim_{x \rightarrow x_0} \frac{g(x) - g(x_0)}{x - x_0} = \lim_{x \rightarrow x_0}f[a_1,a_2,...,a_n,x, x_0] = f[a_1,a_2,...,a_n,x_0,x_0]$$

And I'm not sure here about the last equality. I read somewhere that it's true but only, when $a_i \neq a_j$ for $i \neq j$, but I don't know where does it come from. Could you please explain to me why?