I'm doing the following question
let $f(t) = x^6/100$ find $f^\prime(x)$
is this just asking for the basic derivative of $x^6/100 = 3x^5/50$
or does the $t$ in $f(t)$ imply something else?
I'm doing the following question
let $f(t) = x^6/100$ find $f^\prime(x)$
is this just asking for the basic derivative of $x^6/100 = 3x^5/50$
or does the $t$ in $f(t)$ imply something else?
If $f(t)=\frac{1}{100}x^6$ then $f$ does not depend on the variable $t$. Hence differentiation with respect to $t$ gives $f'(t)=0.$