derivatives let $f(t) = x^6/100$

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I'm doing the following question

let $f(t) = x^6/100$ find $f^\prime(x)$

is this just asking for the basic derivative of $x^6/100 = 3x^5/50$

or does the $t$ in $f(t)$ imply something else?

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If $f(t)=\frac{1}{100}x^6$ then $f$ does not depend on the variable $t$. Hence differentiation with respect to $t$ gives $f'(t)=0.$

0
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If it's not a typo, then $f'(x)=0$ because the variables are independent. However, it is probably a typo, because else the question is too easy. In this case, $f'(x)=\frac{3x^5}{50}$