Derived Algebra is nilpotent implies the lie algebra is solvable

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How does one show that Derived Algebra is nilpotent implies the lie algebra is solvable.

My attempt: Let $L$ be such a Lie-algebra then $[L,L]$ is nilpotent so it is solvable. So $[L,L]^{(n)}=0$ for some $n$. What can I do after this?