$$A= \left[\matrix{0& 0& 0& 0& 0& 0& 0& 0& 0& 1\\ 0& 0& 0& 0& 0& 0& 0& 0& 1& 1\\ 0& 0& 0& 0& 0& 0& 0& 1& 1& 1\\ 0& 0& 0& 0& 0& 0& 1& 1& 1& 1\\ 0& 0& 0& 0& 0& 1& 1& 1& 1& 1\\ 0& 0& 0& 0& 1& 1& 1& 1& 1& 1\\ 0& 0& 0& 1& 1& 1& 1& 1& 1& 1\\ 0& 0& 1& 1& 1& 1& 1& 1& 1& 1\\ 0& 1& 1& 1& 1& 1& 1& 1& 1& 1\\ 1& 1& 1& 1& 1& 1& 1& 1& 1& 1\\ } \right]$$
Q: What does the spy(A') output look like? Describe?
I have been able to find A' (A Trnapose) in Matlab, and it looks identical to the original A matrix. However, I can't seem to figure out why I'm getting the original matrix back!
The transpose just takes each ith column of the original matrix and assigns it to the ith row of the transposed.
What does this do to your particular matrix?