So multiplying a row by a constant multiple the determinant by the same constant and swapping 2 rows will multiply the determinant by a negative right and adding or subtracting does not change the matrix.
What if......
$$\begin{vmatrix} a&b&c \\ d&e&f \\ g&h&i \end{vmatrix} = determinant = -6$$
so swapping two rows will equal to a determinant positive 6 and multiplying by (1/3) will make determinant equal -2
But the question asks......
$$\begin{vmatrix} a&b&c \\ d&e&f \\ 2a&2b&2c \end{vmatrix}$$
I don't understand how you can change the first matrix into this one at all. At the best i know 2 of row at least was added so that equations now change in determinant bu ti dunno how g h i are eliminated.
The determinant you want to calculate is equal to zero because the third line is 2 times the first line. It doesn't matter the determinant of the first matrix you wrote.