{$(a, b) | a∈Z^{+}, b∈Z^{+}, a = 3^{n}b, where n∈N$} (N is the set of natural numbers)
{$(a, b) | a∈Z^{+}, b∈Z^{+}$, a >2b or b >2a}
{$(a, b) | a∈Z^{+}, b∈Z^{+}$, a ≡ 0 (mod b) or b ≡ 0 (mod a)}
{$(a, b) | a∈Z^{+}, b∈Z^{+}, a = 3^{n}b, where n∈N$} (N is the set of natural numbers)
{$(a, b) | a∈Z^{+}, b∈Z^{+}$, a >2b or b >2a}
{$(a, b) | a∈Z^{+}, b∈Z^{+}$, a ≡ 0 (mod b) or b ≡ 0 (mod a)}
All three relations are of the form $$aRb\quad \text{ if }\frac{a}{b}\in S$$ where $S$ is some subset of $[0,+\infty]$. Namely,
(One can observe that formally setting $0/0=1$ fits in all three cases.)