I can't seem to figure this out, so I hope someone could help me.
I need to determine the equations of the planes that go through the coordinate axis and which are perpendicular to a given plane (Q): $3x-4y+5z-12=0$.
I can't seem to figure this out, so I hope someone could help me.
I need to determine the equations of the planes that go through the coordinate axis and which are perpendicular to a given plane (Q): $3x-4y+5z-12=0$.
Let $\vec{n}(a,b,c)$ be a normal of the plane.
Thus, $3a-4b+5c=0$ and if you mean the $x$-axis then $a=0$ and we got the equation $$5y+4z=0.$$