The fuel consumption for a ships voyage varies directly was the (mass of the ship)^2/3 , varies directly as the (speed of the ship)^2 and varies directly as the distance of the voyage.
For a particular voyage a ship has a fuel consumption of 250 tonne. Determine the consumption for a new voyage of 15% increased distance, at an increased speed of 5% and with the mass reduced by 10%
Taking the mass of the ship to be "M", the speed to be "S", and the distance of the voyage to be "D", the fuel consumption is $FC= KM^{2/3}S^2D$ for some constant, K.
For "15% increased distance, at an increased speed of 5% and with the mass reduced by 10%" D changes to 1.15D, S changes to 1.05S and mass changes to 0.90M.
4 The fuel consumption changes to $K(0.90M)^{2/3}(1.05S)^2(1.15D)= (kM^{2/3}S^2D)((0.90^{2/3})(1.05^2)(1.15))$.