Find projection matrix $P$ (by projecting bases of $\mathbb R^3$ over the given plane.)
Hence, projection of a vector $b$ onto the plane will be $Pb$. Let the reflection of $b$ over the plane be $x$.
Now you know that, foot of projection is the middle point of line joining $b$ and $x$ and therefore, $Pb=(b+x) /2\implies (2P-I_3)b=x$, where $I_3$ is the identity matrix of order $3\times 3$
Reflection matrix is $2P-I_3$ because it transforms any vector(b) in $\mathbb R^3$ into its reflection over the given plane.
Hint:
Reflection matrix is $2P-I_3$ because it transforms any vector(b) in $\mathbb R^3$ into its reflection over the given plane.