I am trying to find the period of,
$$f(x) = (\sin2x)^2$$
So I know how to determine the period of $ f(x) = \sin2x $ by the following,
$$f(x) = 2(\sin x)$$
Using the formula $P = \dfrac{2\pi}{|B|}$ here $B$ would be $2$ so, $P = \dfrac{2\pi} 2 = \pi.$
So then how could I solve my original problem? I am not sure how to solve this with the squared function
Less wordy: $\sin^2{2x}=\frac{1}{2}-\frac{1}{2}\cos4x$. What is the period of $\cos4x$?