Determining the correct upper bound for an integral in polar coordinates

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This seems super easy. But i am just a little bit stuck here. Haven't done much calculus recently. Can someone help me out real quick?

Thank you in advance!

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Hint:

$$z=\sqrt{x^2+y^2}\implies 18=x^2+y^2+z^2=2(x^2+y^2)\implies x^2+y^2=9$$

Well now: do you remember what $\,r\,$ is in polar coordinates...?