The question is:
Is every complex matrix such that $A^2=A$ diagonalizable?
My reasoning goes as follows: If $A^2=A$ then left multiplying the inverse of $A$ on both sides yields $A=I$. I'm pretty sure this shouldn't be that easy.
2026-04-26 03:21:03.1777173663
Diagonalizable Matrix over the complex field
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$P=X^2-X=X(X-1)$ is a split simple root polynom which cancel $A$, so $A$ is diagonalizable.