Diagonalization of nxn matrice

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What conditions must a nxn matrice have to always be diagonalizable? I do know that it has to have n distinct eigenvalues but let's say if the only information we had is that if 0 is one of its eigenvalues then can it still be diagonalised? I personally don’t think so but i would just want to be sure of it. One of the other important conditions is that say matrice B

B= $\lambda$I for where $\lambda$ is not 0 right?