Did I calculate this indefinite integral correctly?

Question

The question:

"$f'(x)=6x^{4.3}+5x^{-4.5}+6x^{0.6}$ and $f(1)=-11$. What is $f(x)$?"

So I entered the problem in as $\int 6x^{4.3}+5x^{-4.5}+6x^{0.6}\,dx$ . This gave me $\frac{-1.42857}{x^(3.5)}+3.75x^{1.6}+1.13208x^{5.3}+c$

I then used $f(1)=-11$ and substituted it in as

$-11=\frac{-1.42857}{(1)^(3.5)}+3.75(1)^{1.6}+1.13208(1)^{5.3}+c$

And this gave me the constant to be $\frac{-1445351}{100000}$

The proper answer I am given however is

$\frac{6}{5.3}x^{5.3}-\frac{5}{3.5}x^{-3.5}+\frac{6}{1.6}x^{1.6}-11-\frac{6}{5.3}+\frac{5}{3.5}-\frac{6}{1.6}$

where did I go wrong and can someone show me how to do it correctly?

Answer 1

Both the answers are correct.The answer provided, didn't convert the fractions to their decimal expansions.

Also ,I read your statement "..So I entered the problem in as $∫6x4.3+5x−4.5+6x0.6dx$ . This gave me $−1.42857x(3.5)+3.75x1.6+1.13208x5.3+c$...".

Did you use calculator for it?If yes, then the answer provided hints that there was no use of it.