My question is about infinity and $0$. Using the same logic as $0.999...$ is equal to $1$, if a number is depreciating towards $0$ infinitely at a constant rate (say it is being constantly divided by two), would it be correct to say that it would eventually reach $0$. The graph would have an asymptote of $0$, because there are an infinite amount of numbers less than $1$. But if there are an infinite amount of $0$s after the decimal point, even if they are eventually followed by a $1$, would it equal $0$? It is hard to comprehend because if the $0$s go on infinitely, the $1$ would never actually exist or have a value.
I guess my question is: Would it ever get to a point where a number approaching $0$ would actually be considered $0$? I feel like it shouldn't since there would always be at least one digit that isn't a $0$, but it also feels like if there are an infinite number of $0$s, then the number is equal to $0$.
You mention an example: repeatedly dividing by 2. If you start with a number $c \neq 0$ and divide it by $2$ exactly $n$ times, you are left with the number $c / 2^n$. Even if you perform a large number of divisions (e.g., $n=1000$ or $n=$ Graham's number), $c / 2^n$ will always be nonzero.