Let $R$ be a commutative ring.
What are propositions about $R$-modules that do not generally hold but are true when $R$ is a field?
So-called "fundamental theorem of linear algebra"
$$(\mathrm{Im} f)^\perp=\mathrm{Ker} f^*$$
is not a feature of linear spaces, because for any $R$-homomorphism $f:M\to N$ between $R$-modules,
$$\begin{align} \varphi \in (\mathrm{Im} f)^\perp &\Leftrightarrow \forall n \in \mathrm{Im}f. \varphi(n)=0\\ &\Leftrightarrow \forall m\in M. \varphi(f(m))=0\\ &\Leftrightarrow f^*(\varphi)=0\\ &\Leftrightarrow \varphi\in \mathrm{Ker}f^*. \end{align}$$
I know only two examples.
- Basis theorem. Every linear space has a basis, but not all modules.
- If $a_1, \dots, a_m$ are linearly dependent, one of them is a linear combination of others.
(linear space theory) - (module theory) = (dimension theory)?
If $a_1, \dots, a_m\in V$ are linearly independent and $b_1, \dots, b_n \in V$ spans $V$, $m\leq n$ holds. However, this is also true for modules over a commutative ring(link).
Many properties of linear spaces can be generalized to $R$-modules. I want to know counterexamples.
The "most important" fact about vector spaces which fails for modules in general is exactly what you noted: every vector space has a basis, but not every module has a basis. Indeed, the following are equivalent (for the rest of this post, $R$ will be a commutative unital ring):
Another commonly-used fact in linear algebra is that every subspace has a complementary subspace. Rings for which this is true of all submodules need not be fields, but they are nicely classified. Precisely, the following are equivalent:
For many properties (in the language of modules) we have a good understanding of the rings $R$ for which the property holds for all $R$-modules. Do you have any specific properties you're curious about? It's a bit silly to ask for examples of properties of vector spaces and modules for which those properties don't hold: there are simply too many to list.