Let $f=\frac x{y^2}$ be a positive function defined on the domain $x>0$ and $y>0$. I want to express $f$ as $g-h$ where both g and h are convex. Is there an easy way to do that?
2026-03-29 08:35:24.1774773324
Difference of convex functions for $x/y^2$
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Is $$\frac{x}{y^2}=\left(x+\frac1{2y^2}\right)^2-\left(x^2+\frac1{4y^4}\right)$$ easy enough?