differential equation $y' = \frac{-2x-y}{-5x+2y}$

Question

[my attempt] setting $u=\frac{y}{x}$ I got $\int\frac{(2u-5)du}{2(u-1)^2}=-\int\frac{dx}{x}$ what should be the next step ?

Answer 1

write $$y'=\frac{-2+\frac{y}{x}}{-5+2\frac{y}{x}}$$ and with $$y=ux$$ we get $$y'=u'x+u$$ $$u'x=\frac{2u^2+6u-2}{2u-5}$$ is separable