can you help me solve this one?
$2x+y=32 \\2p+q=17\\y+6q=?$
I got $0=0$ so I guess I failed somewhere on the way.
From the first equation: $$y=32-2x$$ from the second equation: $$ q=17-2p $$
so you can find $$ y+6q=32-2x+6(17-2p) $$
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From the first equation: $$y=32-2x$$ from the second equation: $$ q=17-2p $$
so you can find $$ y+6q=32-2x+6(17-2p) $$