Find an approximation to $ {25}^{\frac{1}{3}}$ correct to within $10^{-4}$ using the Bisection algorithm.
How to solve it?
Where are the function and interval here?
2026-05-06 02:14:23.1778033663
Difficulty to solve the exercise of Bisection method.
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The most natural function is $f(x)=x^3-25$. You need an interval $[a,b]$ such that $f(a)$ and $f(b)$ have different signs. Take $a=0$ and $b=25$ for instance.