$\operatorname{End}_{\mathbb C} \mathbb H$ is an $8$-dimensional real vector space.
Is there a simple way to see this?
$\operatorname{End}_{\mathbb C} \mathbb H$ is an $8$-dimensional real vector space.
Is there a simple way to see this?
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$\mathbb H$ is a $2$-dimensional $\mathbb C$ vector space, so $\operatorname{End}_\mathbb C(\mathbb H)\cong M_2(\mathbb C)$. The latter is, of course, is $8$ dimensional considered as an $\mathbb R$ vector space.