In my Discrete Math course, I encounter a question such as $$\exists x\forall y\,x<y \text{ where }x,y\in\mathbb{Z}\,,$$ and I explain it like this: "Let $x=1$ and $y=-2$ For an $x$ in the universe not all $y$ values make the statement $x < y$ true so the case is $1$ is not equal $-2$" and I think this is sufficient for explaining but I wonder whether there is a way to indicate proof with symbols or mathematically. Thanks in advance.
2026-04-08 09:42:43.1775641363
Discrete Math quantifiers,proof and demonstrating with symbols
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1
With quantifiers, you can't choose the specific values in all cases. In particular:
What you've done is proved that there is a particular $x$ that the statement doesn't hold for. But that doesn't mean that there isn't another value that it does hold for! (Or at least, it doesn't inherently mean that). If you're showing there doesn't exist an $x$, you need to show that the statement $\forall y \ldotp x < y$ is false for every single $x$, not just a specific $x$.