It is understood that for the sequence of disk automorphisms
$$\frac{z-a_n}{1-\bar{a}_nz},$$
if $a_n\to a\in D_1$, then this sequence converges uniformly on compact subsets of $D_1$ to the automorphism
$$\frac{z-a}{1-\bar{a}z}.$$
I was wondering what we might be able to say about the converse of this statement? Namely, if
$$\frac{z-a_n}{1-\bar{a}_nz}\to \frac{z-a}{1-\bar{a}z}$$
on compact subsets of $D_1$, is it necessarily true that $a_n\to a\in D_1$?
2026-03-29 21:58:12.1774821492
Disk Automorphism and Convergence of Zero
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If the functions $f_n(z) = \frac{z-a_n}{1-\bar{a}_nz}$ converge to $f(z) = \frac{z-a}{1-\bar{a}z}$ in the unit disk then $$ -a_n = f_n(0) \to f(0) = -a $$ so that necessarily $a_n \to a$.