there are 100 pennies and 10 children
every child can get either 5, 10 or 20 pennies
How many ways to do in this case?
I assumed that n = pennies, and k = children
so if first child can get 5, 10 or 20 pennies which is n-5, n-10, or n-20
if I keep going like that, It feels like i am counting all possibilities.
I just don't know how to approach and solve this question.
Consider the expansion of $(x^5 + x^{10} + x^{20})^{10}$. The result you want will be the coefficient of $x^{100}$ in the expansion.
Wolfram Alpha says it is $\boxed{4351}$.