I ran across this example the other day and was surprised at how stumped I was. Suppose $U$ is a uniform random variable on the interval $[0,1]$. Let $F = \frac{1}{U+3}$. What is:
$\operatorname{Cov}(U,F)$?
$f_{F\mid U}(x\mid u)$?
$E[F\mid U=u]$?
I ran across this example the other day and was surprised at how stumped I was. Suppose $U$ is a uniform random variable on the interval $[0,1]$. Let $F = \frac{1}{U+3}$. What is:
$\operatorname{Cov}(U,F)$?
$f_{F\mid U}(x\mid u)$?
$E[F\mid U=u]$?
Since $F$ is an invertible function of $U$, the conditional distribution of $F$ given $U=u$ has only a single point and is hence degenerate.
For the first one, note that $\text{Cov}(U,F)=E(UF)-E(U)E(F)$.