Let $R_{p_k\#}$ be the set of elements in the reduced residue system modulo $p_k\#$.
Let $|R_{p_k\#}|$ be the number of elements in this set.
If $p_i < p_k$ and $p_i$ divides $|R_{p_k\#}|$, does it follow that there are:
$\frac{|R_{p_k\#}|}{p_i}$ elements in $R_{p_k\#}$ inclusive between $1$ and $\frac{p_k\#}{p_i}$
$\frac{|R_{p_k\#}|}{p_i}$ elements in $R_{p_k\#}$ between $\frac{p_k\#}{p_i}$ and $\frac{2p_k\#}{p_i}$
$\dots$
$\frac{|R_{p_k\#}|}{p_i}$ elements in $R_{p_k\#}$ between $\frac{(p_k-1)p_k\#}{p_i}$ and $\frac{(p_k)p_k\#}{p_i}$
For example:
$R_{7\#} = \left\{1, 11, 13, \dots, 209\right\}$ and $|R_{7\#}| = 48$
$3 < 7$ and $3$ divides $|R_{7\#}|=48$ and:
There are $16$ elements between $1$ and $\frac{210}{3} = 70$ which are: $\left\{1, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67\right\}$
There are $16$ elements between $70$ and $140$ which are: $\left\{71, 73, 79, 83, 89, 97, 101, 103, 107, 109, 113, 121, 127, 131, 137, 139\right\}$
There are $16$ elements between $140$ and $210$ which are: $\left\{143, 149, 151, 157, 163, 167, 169, 173, 179, 181, 187, 191, 193, 197, 199, 209\right\}$
Is this always the case? If not, could you provide an example where it is not true? If yes, could you provide the reasoning.
Thanks,
-Larry
I believe that the answer is yes.
Here's my argument:
Let $p_i$, $p_k$ be any two primes such that $i < k$
Let $R_x$ be the reduced residue system modulo $x$ where $|R_x|$ is the number of elements in $R_x$
Assume $p_i$ divides $|R_{p_k\#}|$
Let $\varphi(x)$ be Euler's totient function so that we have $\varphi(p_k\#) = |R_{p_k\#}|$
$\varphi(\frac{p_k\#}{p_i}) = \frac{\varphi(p_k\#)}{p_i - 1}$
So $p_i$ divides $\varphi(\frac{p_k\#}{p_i})$
Using the same analysis found in this answer to a previous question, the elements of the reduced residue class modulo $\frac{p_k\#}{p_i}$ divide equally into the congruence classes modulo $p_i$.
So, it follows that $\frac{p_i - 1}{p_i}$ of the reduced residue class of $\frac{p_k\#}{p_i}$ are also relatively prime to $p_k\#$.