Do the Hurwitz quaternions form a cyclic group?

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I am investigating applications of the Hurwitz quaternions: https://en.wikipedia.org/wiki/Hurwitz_quaternion $$H_u = \left\{a+bi+cj+dk\mid (a,b,c,d) \in\mathbb{Z}\mbox{ or }(a,b,c,d) \in\mathbb{Z}+\frac{1}{2}\right\}$$

As an additive group, H is free abelian with generators $\dfrac{1 + i + j + k}{2}, i, j, k$

I'm trying to define modulo and square root for the Hurwitz quaternions, so I can express a large Hurwitz prime as a congruence of two smaller integers: $p \equiv 3 \text{ mod } 4$ where p is a Hurwitz prime, similar to the Rabin cryptosystem

One way I know of doing this is by knowing that $H$ forms a cyclic group. I am not sure how to determine that or prove it, as my math knowledge is limited. Any help or guidance is appreciated!

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No, this group is not cyclic as it is free abelian of rank $4$. A free abelian group is cyclic if and only if the rank is $1$, i.e., if it has a basis with $1$ element.

Moreover the unit group of the Hurwitz quaternions is a split extension of the quaternion group $Q_8$ and the cyclic group $C_3$ and hence also not cyclic, see here.