Do we have $(f^{-1}\widetilde{A^{(I)}})(D(g))\simeq ((f^{-1}\widetilde{A})(D(g)))^{(I)}$?

18 Views Asked by At

Let $f:\operatorname{Spec}B\to \operatorname{Spec}A$ be a morphism of schemes. Given a set $I$, $\forall g\in B$, do we have $(f^{-1}\widetilde{A^{(I)}})(D(g))\simeq ((f^{-1}\widetilde{A})(D(g)))^{(I)}$?