Does $L^p(L^1([0,1]))$ make sense?

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I'm examining several function spaces like $L^p(X,\mu)$ where $X$ is a Banach space.

Is it possible to take $X = L^1([0,1])$ and then look at $L^p(X)$?

The problem I have is that I don't know what kind of measure $X=L^1([0,1])$ should have, and therefore I'm not sure whether $L^p(L^1([0,1]))$ makes sense.