Does $\lim_{k}\sup_{w \in H} \langle f_k, w \rangle_{H^*, H} = \sup_{w \in H} \lim_{k} \langle f_k, w \rangle_{H^*, H}$ for a weak-star convergence?

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Suppose $H$ is a Hilbert space, and we have a sequence $f_k \rightharpoonup f$ in $H^*$ (the sequence in $H^*$ converges weakly in $H^*$). This implies that $f_k \rightharpoonup^* f$ in $H^*$ (weak-star convergence).

I have a question. Is it possible to commute limit and suprema like this:

$$\lim_{k \to \infty}\sup_{w \in H, \\\lVert w \rVert = 1} \langle f_k, w \rangle_{H^*, H} = \sup_{w \in H\\ \lVert w \rVert = 1} \lim_{k \to \infty} \langle f_k, w \rangle_{H^*, H}$$

Usually I would immediately say no in general, but we do have a weak-star convergence, and I read that this is much nicer than the usual one, so I wonder if it holds?