Does the Axiom of choice allow the existence of a choice set before the end of its enunciation?

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We can state the Axiom of Choice as follows: 'If A is a family of nonempty sets, then there is a function f with domain A such that f(a) ∈ a for every a ∈ A. Such a function f is called a choice function for A'.

However, if A may be any family of nonempty sets, it may also include the set that we create through the choice of exactly one element from a known collection of nonempty sets. That is, if we allow any set to exist in the first place, we either do not need a choice function to create a new set, or we tacitly assume that at the beginning the choice function only applies to certain collections of sets. But since the Choice Set is a set, then after its statement of existence we may apply the choice function to the collection including this set and other sets to create a new set that did not exist before.

Am I wrong? My problem is: which sets are allowed to exist before the statement of existence of the Choice set?

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Axioms do not create sets. Axioms let us prove that some objects, in this case sets, exist. But existence is not predicated on provability.

Some families of sets admits a choice function, and that much is provable without the axiom of choice. If a family does not admit a choice function, then sets from which you can construct a choice function also do not exist.