Does the completion of an operator with closed image also have a closed image?

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Let $X,Y$ be real normed vector spaces, and suppose that $T:X \to Y$ is a bounded linear operator with closed image.

Let $\tilde X,\tilde Y$ be the completions of $X,Y$, and let $\tilde T:\tilde X \to \tilde Y$ be the natural continuous extension of $T$ (which is unique).

Is $\text{Image } \tilde T$ closed in $\tilde Y$?

I proved that $\, \, \overline{\text{Image } \tilde T}^{\tilde Y}= \overline{\text{Image } T}^{\tilde Y} $, however, this doesn't seem to resolve the question. (We only know $\text{Image } T$ is closed in $Y$; it does not need to be closed in $\tilde Y$).