Does the $\Omega$-spectrum functor send exact triangles to homotopy cofiber sequences?

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The functor $\Omega^\infty\colon Spectra\to Spaces$ which takes a spectrum, replaces it by the associated $\Omega$-spectrum and then takes its $0$th space sends exact triangles to homotopy fiber sequences.

Does $\Omega^\infty$ send exact triangles of spectra to homotopy cofiber sequences of spaces?

For spectra, homotopy cofiber sequences, homotopy fiber sequences and exact triangles are the same.

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I think it doesn't, which kinda makes sense since it is a composite of a left and a right adjoint.

More precisely : takes a short exact sequence of abelian groups $0 \to A \to B \to C \to 0$, then you get an exact triangle of spectra $HA \to HB \to HC$. If you rotate, or suspend once you get $\Sigma HA \to \Sigma HB \to \Sigma HC$ which is also exact, but the $0$-spaces are $K(A,1) \to K(B,1) \to K(C,1)$, i.e., the classifying spaces $BA \to BB \to BC$.

Now, the functor $B(-)$ sends short exact sequences of discrete abelian groups to fiber sequences but not cofiber sequences, for example take $0 \to \mathbb{Z} \stackrel{\cdot 2}{\to} \mathbb{Z} \to \mathbb{Z}/2 \to 0$ which becomes $S^1 \to S^1 \to RP^{\infty}$ which is not a cofiber sequence as can be seen in homology.