Does the series $ \ \sum_{n=1}^{\infty} (-1)^{n-1} \frac{x^2+n^2}{n^3} $ converges uniformly on $ \ \ \ [-1,1] \ $?
Answer:
$ \ \sum_{n=1}^{\infty} (-1)^{n-1} \frac{x^2+n^2}{n^3} \\ =\sum_{n=1}^{\infty} (-1)^{n-1} \frac{x^2}{n^3}+ \sum_{n=1}^{\infty} (-1)^{n-1} \frac{1}{n} \\ \leq \sum_{n=1}^{\infty} (-1)^{n-1} \frac{1}{n^3}+ \sum_{n=1}^{\infty} (-1)^{n-1} \frac{1}{n} , \ (\because |x| \leq 1 ) \\ = A+B $
Since both the series $ \ A,B \ $ are alternating series , both converges uniformly on $ \ [-1,1] \ $.
So the given series converges on $ \ [-1,1] \ $ uniformly.
But I am not sure of my work.
Please someone verify my work .
This is not correct. Why would those inequalities be true?
You can prove that the series converges uniformly using Dirichlet's test: