Does there exist the following theorem for complex case?

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‎Consider the following theorem (see theorem 7.17 of [W. Rudin. Priniciples of Mathematical Analysis, Mcgraw-Hilly, 1976.])‎

Theorem. Suppose ‎$‎\{f_n\}‎$ ‎is ‎sequence ‎of ‎functions, ‎differentiable ‎on ‎‎$‎[a,b]‎$ ‎and ‎such ‎that‎ $‎\{f_n(x_0)\}‎$ converges for some point ‎$x_0‎$‎ ‎on ‎‎$‎[a,b]‎$. If ‎$‎\{f'‎_n\}‎$ converges uniformly‎ ‎on ‎‎$‎[a,b]‎$, then ‎$‎\{f_n\}‎$ converges uniformly‎ ‎on ‎‎$‎[a,b]‎$ to a function ‎$‎f‎$ ‎and‎‎

\begin{align*} f'‎(x)=‎\lim‎_{n\to\infty}‎‎f'‎_n(x),\;\;a\leq x \leq b. \end{align*}

‎>‎I ‎know ‎that ‎the ‎Theorem is stated for ‎real ‎case‎, but in my research I dealt to complex case and ‎‎Now my question is :‎‎

Does there exist the above (or similar) theorem for complex case? (i.e., Suppose ‎$‎\{f_n\}‎$ ‎is ‎sequence ‎of complex ‎functions, ‎differentiable ‎on an open domain ‎$‎D‎$‎ ‎and ‎such ‎that‎ $‎\{f_n(z_0)\}‎$ converges for some point ‎$z_0‎$‎ ‎on an open domain ‎$‎D‎‎$. If ‎$‎\{f'‎_n\}‎$ converges uniformly‎ ‎on ‎‎an open domain ‎$‎D‎$, then ‎$‎\{f_n\}‎$ converges uniformly‎ ‎on an open domain ‎$‎D‎$ to a function ‎$‎f‎$ ‎and‎‎ ‎‎‎$f'‎(z)=‎\lim‎_{n\to\infty}‎‎f'‎_n(z),\;\;z\in ‎D‎‎.‎‎$‎‎‎)? If yes, what is refrences. Anyone can help me? Thanks in advance. ‎

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Here is one version of the theorem for the complex case

Let $D$ be a convex open set and $f_n,f$ be holomorphic functions on $D$. If $f_n'$ converges uniformly on compact subsets of $D$ and $f_n(z_0) \to f(z_0)$ for some $z_0$ then there is a holomorphic function $h$ such that $f_n \to h$ uniformly on compact subsets and $\lim f_n'(z)=h'(z)$.

Proof: $f_n(z)=f_n(z_0)+\int_{[z_0,z]}f_n'(w)dw$ where $[z_0,z]$ denotes the line segment from $z_0$ to $z$. if $g$ is the limit of $f_n'$ the we see that $f_n$ converges uniformly on compact stes to a funtion $h$ such that $h(z)=f(z_0)+\int_{[z_0,z]}g'(w)dw$. This implies that $h'=g$.