doesn't solving for linear independence require the use of linear algebra?

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wouldn't that be circular logic?

what I mean is

-solving linear independence is an earlier topic

-solving systems of linear equations is a later topic

But to do linear independence requires solving systems of linear equations which we haven't covered yet.


For example, determine if the set

$$ S = {\{(1, −1, 2),(1, −2, 1),(1, 1, 4)}\} $$

of three vectors in $\Bbb R^3$ is independent or dependent.

Is there a nontrivial solution to the vector equation x(1, −1, 2) + y(1, −2, 1) + z(1, 1, 4) = (0, 0, 0)?

Solve the system of homogeneous linear equations

x + y + z = 0

−x −2y + z = 0

2x + y + 4z = 0


I hope I am making sense.

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Linear independence of vectors is a basic concept defined independently in ealier topic and which requires, in general, the solution of a homogeneous system of linear equation to be checked.

There is a link between the two concept but there is not any circular logic in that.