Can someone please help me as to how to calculate this double integral using polar co-ordinates - please see attached picture: double int. polar co-ords
2026-03-31 16:51:29.1774975889
Double Integral using Polar Co-ordinates
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$$I=\int_{0}^{\sqrt{3}} \int_{\frac{\pi}{4}}^{\frac{\pi}{2}}r^{\frac{3}{2}} \ d \theta \ dr=$$ $$= \frac{\pi}{10}3^{\frac{5}{2}}$$