There's a question in a book,
16 2/3% of 600 gm - 33 1/3% of 180 gm
I was solving it like regular method which i use to find x% of a number, for eg.
20% of 200 =1/5*200=40.
But, when I convert mixed fraction (16 2/3%) into improper fraction (50/3), and then multiply it by 600 the result I get is wrong.
The book has a different formula of solving it:
[(50/3) * (1/100) * (600)] - [(100/3) * (1/3) * (180)]
I cant understand why should I add (1/100) in between the (50/30) and 600.
And why is there (1/3) in between (100/3) and 180.
Thanks in advance
$16 \frac{2}{3}\% \text{ of } 600 \text{gm} - 33 \frac{1}{3}\% \text{ of } 180 \text {gm}$
$\frac{50}{3}\% \text{ of } 600 \text{gm} - \frac{100}{3}\% \text{ of } 180 \text {gm}$
$\frac{50}{3}\% \times 600 \text{gm} - \frac{100}{3}\% \times 180 \text {gm}$
$\frac{50}{3} \times \frac{600}{\textbf{100}} \text{gm} - \frac{100}{3} \times \frac{180}{\textbf{100}} \text {gm}$
$\frac{50}{3} \times 6 \text{gm} - \frac{180}{3} \text {gm}$
$100 \text{gm} - 60 \text {gm} =\boxed{40\text{gm}}$.
To answer your query: whenever you remove the $\%$ you have to divide by $\textbf{100}$.