Doubt in Fraction and percentage

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There's a question in a book,

16 2/3% of 600 gm - 33 1/3% of 180 gm

I was solving it like regular method which i use to find x% of a number, for eg.

20% of 200 =1/5*200=40.

But, when I convert mixed fraction (16 2/3%) into improper fraction (50/3), and then multiply it by 600 the result I get is wrong.

The book has a different formula of solving it:

[(50/3) * (1/100) * (600)] - [(100/3) * (1/3) * (180)]

I cant understand why should I add (1/100) in between the (50/30) and 600.

And why is there (1/3) in between (100/3) and 180.

Thanks in advance

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$16 \frac{2}{3}\% \text{ of } 600 \text{gm} - 33 \frac{1}{3}\% \text{ of } 180 \text {gm}$

$\frac{50}{3}\% \text{ of } 600 \text{gm} - \frac{100}{3}\% \text{ of } 180 \text {gm}$

$\frac{50}{3}\% \times 600 \text{gm} - \frac{100}{3}\% \times 180 \text {gm}$

$\frac{50}{3} \times \frac{600}{\textbf{100}} \text{gm} - \frac{100}{3} \times \frac{180}{\textbf{100}} \text {gm}$

$\frac{50}{3} \times 6 \text{gm} - \frac{180}{3} \text {gm}$

$100 \text{gm} - 60 \text {gm} =\boxed{40\text{gm}}$.

To answer your query: whenever you remove the $\%$ you have to divide by $\textbf{100}$.