Attaching Snapshot
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[FromSection 1.5of the book Advanced Calculus for Applications By Francis B. Hildebrand]
I am learning differential equations, but I am having difficulty in understanding what author is trying to convey in the section enclosed inside the blue bracket?
I know $$\frac{\partial[ L{e}^{rx}]}{\partial r}=0 $$ at $r=r_1$ but I cannot follow how this leads to the conclusion for giving the solution?
If you differentiate the first expression in the blue box using the product rule and the chain rule the result will still have $(x-r_1)$ as a factor because $(x-r_1)$ occurs in the original with an exponent greater than $1$.