Easy number theory/proof by induction

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This is my attempt to solve the following question: "Use induction to show that if $(a,b)=1$ (greatest common divisor of $a$ and $b$), then $(a,b^n)=1$ for all $n\geq 1$."

We have that $(a,b)=1$, which implies that $1=au + bv$ for some integers $u,v$. For the induction, assume that $(a,b^k)=1$, which implies $1=ar + b^{k}s$ for some integers $r,s$. Multiplying these equations together yields $1=(au + bv)(ar + b^{k}s)$. We then get

$$1=a^{2}ur + aub^{k}s + bvar + b^{k+1}vs$$ which simplifies to $$1=a(aur + ub^{k}s + bvr) + b^{k+1}vs$$.

$(a,b^{k+1})$ divides the right side of the equation, which implies that $(a,b^{k+1})$ also divides the left side of the equation, and since $(x,y)$ of any integers $x$ and $y$ is at least $1$, it follows that $(a,b^{k+1})=1$. This completes the proof by induction, since we have assumed our base case of $n=1$.

I would greatly appreciate any feedback if any of the steps in the solution are wrong. Thanks in advance.

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This solution is correct, very clear, and easy to follow. Well done!

The only downside is that this question is very easily generalisable and your proof method is very specific.