In how many combinations can I arrange 10 different pens in 5 glasses?
I found this problem but I'm not sure of what exactly is asking. Is it correct to interpret it as a simple combination, namely: $$ \frac{10!}{5!(10-5)!} $$
In how many combinations can I arrange 10 different pens in 5 glasses?
I found this problem but I'm not sure of what exactly is asking. Is it correct to interpret it as a simple combination, namely: $$ \frac{10!}{5!(10-5)!} $$
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Imho it asks you to define in how many groups of 5 pens you can rearrange 10 pen, if (p1,p2,p3...p10) are your pens you have to create N groups like (p1,p2,p4,p7,p9),(p2,p3,p7,p10,p1) in which each group has to be formed by 5 different pens. It's easy to find that in this question you are not interested by the order of the objects but only by their nature so basically your answer is right $$Number\space of \space groups = {10\choose 5} = \frac{10!}{5!(10-5)!}$$
Always simplify you problem in terms of entire set (10 pens) and groups (glasses), it's easier to find which formula you need.