Elements and Unions

Question

Need help solving this problem step by step!

Answer 1

Hint: $R \setminus S =$ everything that is in $R$, but not in $S$.

Answer 2

$B$ is the right answer.

$$R \cap S \neq \varnothing $$

$$x \in R, \text{ BUT } x \notin S, \text{ and as the intersection of R and S is different from the empty set,} \\ \text{ we have to subtract from R all the elements of S }$$