Im following the algorithm for left recursion elimination from a grammar.It says remove the epsilon production if there is any
I have the following grammer
S-->Aa/b
A-->Ac/Sd/∈
I can see after removing the epsilon productions the grammer becomes
1) S-->Aa/a/b
2)A-->Ac/Sd/c/d
Im confused where the a/b comes in 1) and c/d comes in 2) Can someone explain this?